The length of a rectangle is 4 meters less than 3 times it's width. If the perimeter of the rectangle is at most 48 meters, find the greatest possible width of the rectangle

Question

Rachel Golden

Mathematics

12 October, 07:09

The length of a rectangle is 4 meters less than 3 times it's width. If the perimeter of the rectangle is at most 48 meters, find the greatest possible width of the rectangle

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Answers (1)

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Craig Velez · Answer 1

7

Step-by-step explanation:

Think about it visually. 3x-4 is the length and x is the width. Since a rectangle has 2 parralel and equal sides, it's just double those. The equation is 8x-8=48. 48 is the total as given in the problem.

8x-8=48

8x=56

x=7

The width is 7.