An object is thrown upward from the top of an 80 -foot building with an initial velocity of 64 feet per second. The height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the ground?

Question

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Mathematics

27 February, 21:06

An object is thrown upward from the top of an 80 -foot building with an initial velocity of 64 feet per second. The height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the ground?

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Answers (1)

Know the Answer?

Gasby · Answer 1

Step-by-step explanation:

Solving:

Use the formula h = - 16t^2 + vt + s

What we know:

v = 64 feet per second (initial velocity)

s = 80 foot (initial height)

h = ?

t?

h = - 16t^2 + 64t + 80

I know I should be asking in detail, are you allowed to use the quadratic formula or solve it by factoring it out?