the length of a rectangular piece of land is 12cm more than four times its width. the perimeter is 74cm. find its dimensions

length = 32 and width = 5

let the width = w then length = 4w + 12

perimeter = 2 (length + width)

= 2 (4w + 12 + w) = 2 (5w + 12) = 10w + 24

perimeter = 74

solve 10w + 24 = 74

subtract 24 from both sides

10w = 74 - 24 = 50 ⇒ w = 5

width = 5 and length = (4 * 5) + 12 = 20 + 12 = 32