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26 March, 22:19

The area of the surface of the trampoline is equal to twice its perimeter. Find the dimensions of the trampoline.

The length is 4x

the width is (x+6)

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  1. 26 March, 22:32
    0
    A = lw

    A = (x + 6) 4x

    A = (x) 4x + (6) 4x

    A = 4x² + 24x
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