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15 October, 16:43

What's the correct answer for this? Two chords AB and CD intersect at E. If AE = 2cm, EB = 4, and CE = 2.5 cm, find the length of ED

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  1. 15 October, 16:57
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    ED = 3.2 cm

    Step-by-step explanation:

    According to chord-chord power theorem,

    (AE) (EB) = (CE) (ED)

    2*4 = 2.5 * ED

    8/2.5 = ED

    ED = 3.2 cm
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