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21 December, 16:56

By remainder theorem, find the remainder of p (x) when it is divided by g (x), where p (x) = x^3-2x^2-4x-1, g (x) = x+1

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  1. 21 December, 17:24
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    By the remainder theorem the remainder when dividing p (x) by x-a is p (a).

    Dividing by x+1 means we want p (-1).

    p (-1) = (-1) ³ - 2 (-1) ² - 4 (-1) - 1 = - 1 - 2 + 4 - 1 = 0

    Answer: 0

    They go in evenly so x+1 is a factor of p (x).
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