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15 September, 16:54

A parabola has its vertex at (2, 1) and crosses the x-axis at (1,0) anu al l

the equations below has this parabola for its graph? (TEKS A2.4B-R)

ui ...

Ay=1 - (x - 2) ^2

C y = - 1 - (x + 2) ^2

Dy = - 1 - (x - 2) ^2

B

y = 1 + (x + 2) ^2

+3
Answers (1)
  1. 15 September, 16:57
    0
    A

    Step-by-step explanation:

    The equation of a parabola in vertex form is

    y = a (x - h) ² + k

    where (h, k) are the coordinates of the vertex and a is a multiplier

    Here (h, k) = (2, 1), thus

    y = a (x - 2) ² + 1

    To find a substitute (1, 0) into the equation

    0 = a (1 - 2) ² + 1

    0 = a + 1 (subtract 1 from both sides)

    a = - 1

    Hence

    y = - (x - 2) ² + 1 or

    y = 1 - (x - 2) ² → A
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