Ask Question
3 June, 17:57

An arrow is shot upward with a velocity of 64 feet per second. Using the formula h (t) = 64t-16t^2, how long after the arrow is released does it hit the ground?

+5
Answers (1)
  1. 3 June, 18:03
    0
    It hits the ground when h (t) = 0

    -16t^2+64t=0 factor

    -16t (t-4) = 0, we know t>0 so

    t=4 seconds.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An arrow is shot upward with a velocity of 64 feet per second. Using the formula h (t) = 64t-16t^2, how long after the arrow is released ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers