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9 September, 23:29

Complete the square to rewrite y=x^2-6x+14 in vertex form. Then state whether the vertex is a maximum or minimum and give is coordinates. A. - Minimum at (3,5) B. - Minimum at (-3,5) C. - Maximum at (-3,5) D. - Maximum at (3,5)

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  1. 9 September, 23:57
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    3,5, Minimum

    Step-by-step explanation:

    y=x²-6x+14

    y = (x²-2*3x + 3²-3²) + 14

    y = (x²-2*3x+3²) + 14-9

    y = (x-3) ²+5

    a=1

    p=3

    q=5

    a>0 ⇒ vertex is minimum

    V (p, q) ⇒ V (3; 5)
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