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Haylee Aguirre
Mathematics
11 March, 07:19
Factorise 125x^3 - 27y^3
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Agustin James
11 March, 07:36
0
(5x - 3y) (25x² + 15xy + 9y²)
Step-by-step explanation:
125x³ - 27y³ is a difference of cubes and factors in general as
a³ - b³ = (a - b) (a² + ab + b²)
Given
125x³ - 27y³
= (5x) ³ - (3y) ³
= (5x - 3y) ((5x) ² + (5x) (3y) + (3y) ²)
= (5x - 3y) (25x² + 15xy + 9y²)
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