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11 April, 04:15

1+csc (t) / 1+sin (t)

I have to make it into a single trig function

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  1. 11 April, 04:21
    0
    Consider this:

    csc t=1/sin t

    (1 + csc t) / (1 + sin t) = [1 + (1/sin t) ] / (1+sin t) = [ (sin t+1) / sin t] / (1+sin t) =

    =1/sin t = csc t.

    Answer: (1+csc t) / (1+sin t) = csc t
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