One group (A) contains 615 people. Three-fifths of the people in group A will be selected to win $50 fuel cards. There is another group (B) in a nearby town that will receive the same number of fuel cards, but there are 526 people in that group. What will be the ratio of nonwinners in group A to nonwinners in group B after the selections are made? Express your ratio as a fraction or with a colon.

Question

Koda

Mathematics

1 April, 03:36

One group (A) contains 615 people. Three-fifths of the people in group A will be selected to win $50 fuel cards. There is another group (B) in a nearby town that will receive the same number of fuel cards, but there are 526 people in that group. What will be the ratio of nonwinners in group A to nonwinners in group B after the selections are made? Express your ratio as a fraction or with a colon.

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Answers (1)

Know the Answer?

Myla Haney · Answer 1

The answer is 246:157.

Step by Step:

Group A:

First, figure out 1/5 of the people in group A. (615/5 = 123)

Find 2/5 (the amount of people who lost) (123*2 = 246)

Group B:

They received the same amount of fuel cards, so you take 526 - 369 (3/5 of the last group, or the winners, which is the amount of cards they received) = 157.