Find the slope of the line described by 3x + 2y + 1 = 0.

3/2

-2/3

-3/2

-1/2

3x + 2y + 1 = 0

subtract 3x+1 from each side

3x + 2y + 1 - 3x - 1 = - 3x - 1

2y = - 3x-1

divide by 2 on each side

2y/2 = - 3x/2 - 1/2

y = - 3/2 x - 1/2

this is in the form y = mx + b where m is the slope

m = - 3/2

the slope is - 3/2