The function f (x) = x^2 - 2x + 8 is transformed such that g (x) = f (x-2). Find the vertex of g (x).

a. (1,5)

b. (3,7)

c. (1,9)

d. (-1,7)

Question

Heather Burns

Mathematics

9 February, 21:11

The function f (x) = x^2 - 2x + 8 is transformed such that g (x) = f (x-2). Find the vertex of g (x).

a. (1,5)

b. (3,7)

c. (1,9)

d. (-1,7)

+1

Answers (1)

Know the Answer?

Harold West · Answer 1

Step-by-step explanation:

Since g (x) is f (x-2), every time there is a "x" in the f (x) equation, substitute "x-2". So g (x) would be (x-2) ^2-2 (x-2) + 8. Use the method of trial and error: substitute x as 1,-1, and 3, until you found the right vertex. The answer is B (3,7).

The function f (x) = x^2 - 2x + 8 is transformed such that g (x) = f (x-2). Find the vertex of g (x).a. (1,5)b. (3,7)c. (1,9)d. (-1,7)

The function f (x) = x^2 - 2x + 8 is transformed such that g (x) = f (x-2). Find the vertex of g (x).

a. (1,5)

b. (3,7)

c. (1,9)

d. (-1,7)