How many real number solutions does this have 3x^2 + 8x + 7=0

zero

Step-by-step explanation:

The answer to that question is best found by looking at the value of the discriminant.

For quadratic ax^2 + bx + c = 0, the value of the discriminant is ...

d = b^2 - 4ac

Here, you have a=3, b=8, c=7, so the discriminant is ...

d = 8^2 - 4 (3) (7) = 64 - 84 = - 20

When the discriminant is negative, both solutions are complex (not real).

There are zero real solutions to this equation.