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14 April, 08:24

The sum of the first and third of three consecutive integers is 136. Find the three even integers

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  1. 14 April, 08:32
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    The three even integers are 66, 68 and 70

    Solution:

    Let the three consecutive even integers be x, x + 2, x + 4

    Let the first integer be x

    Let the second integer be x + 2

    Let the third integer be x + 4

    Given that, sum of the first and third of three consecutive integers is 136

    Sum of first and third integer = 136

    x + x + 4 = 136

    2x + 4 = 136

    2x = 136 - 4

    2x = 132

    x = 66

    Thus the consecutive integers are:

    first even integer = x = 66

    second even integer = x + 2 = 66 + 2 = 68

    third even integer = x + 4 = 66 + 4 = 70

    Thus the three even integers are 66, 68 and 70
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