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Roberto Mcfarland
Mathematics
3 October, 17:50
Find
dy/du, du/dx, and dy/dx
y = u^2, u=4x+7
+5
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2
)
Diego Ho
3 October, 18:11
0
Y=u² (du/dx[u^n]=n (u^ (n-1)) u')
dy/du=2u (u') = 2u
u=4x+7
du/dx=4
dy/dx = (dy/du) (du/dx) = 2u (4) = 2 (4x+7) (4) = 8 (4x+7)
Answer:
dy/du=2u
du/dx=4
dy/dx=8 (4x+7)
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Susan Jarvis
3 October, 18:17
0
dy/dx = 2u
du/dx==4
and
dy/dx = (dy/du) (du/dx)
=2u (4)
= 8u
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