Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 8 feet and a height of 8 feet. Container B has a diameter of 6 feet and a height of 13 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. To the nearest tenth, what is the percent of Container A that is empty after the pumping is complete?

Question

Tessa Dominguez

Mathematics

17 May, 05:22

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 8 feet and a height of 8 feet. Container B has a diameter of 6 feet and a height of 13 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. To the nearest tenth, what is the percent of Container A that is empty after the pumping is complete?

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Answers (1)

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Gilbert · Answer 1

Answer: 91.4%

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

Considering cylinder A,

Height = 8ft

Diameter = 8 ft

Radius = diameter/2 = 8/2 = 4ft

Therefore,

Volume = 3.14 * 4² * 8 = 401.92ft³

Considering cylinder B,

Height = 13ft

Diameter = 6 ft

Radius = diameter/2 = 6/2 = 3ft

Therefore,

Volume = 3.14 * 3² * 13 = 367.38ft³

The volume of Container A that would be left empty after container B is pumped into it is

367.38ft³

the percent of Container A that is empty after the pumping is complete is

367.38/401.92 * 100 = 91.4%