The some of the squares of two consecutive integers is 145. Find the integers.

X^2 + (x + 1) ^2 = 145;

x^2 + x^2 + 2x + 1 = 145;

2x^2 + 2x - 144 = 0;

x^2 + x - 72 = 0;

You solve the equation; the solutions of the equation are 8 and - 9 (integers);

The two consecutive integers are 8 and 9 or - 9 and - 8.

The 2 numbers are 8 and 9.

8^2=64

9^2=81

81+64=145