A function g (x) has x-intercepts at (1/2,0) and (6,0). Which could be g (x) ?

g (x) = 2 (x + 1) (x + 6)

g (x) = (x-6) (2x - 1)

g (x) = 2 (x - 2) (x-6)

g (x) = (x + 6) (x + 2)

Question

Yurem

Mathematics

29 August, 08:27

A function g (x) has x-intercepts at (1/2,0) and (6,0). Which could be g (x) ?

g (x) = 2 (x + 1) (x + 6)

g (x) = (x-6) (2x - 1)

g (x) = 2 (x - 2) (x-6)

g (x) = (x + 6) (x + 2)

+1

Answers (2)

Know the Answer?

Valeria Harding · Answer 1

Valeria Harding 29 August, 08:30

0

g (x) = (x-6) (2x - 1)

Aydin · Answer 2

g (x) = (x-6) (2x - 1)

Step-by-step explanation:

when you expand, it will be 2x²-13x+6=0

when you factories the quadratic equations,

the answer will be 1/2 and 6

A function g (x) has x-intercepts at (1/2,0) and (6,0). Which could be g (x) ?g (x) = 2 (x + 1) (x + 6)g (x) = (x-6) (2x - 1)g (x) = 2 (x - 2) (x-6)g (x) = (x + 6) (x + 2)

A function g (x) has x-intercepts at (1/2,0) and (6,0). Which could be g (x) ?

g (x) = 2 (x + 1) (x + 6)

g (x) = (x-6) (2x - 1)

g (x) = 2 (x - 2) (x-6)

g (x) = (x + 6) (x + 2)