If the side length of the base of a square pyramid is divided by 4 and the slant height is divided by 3, what is the surface area formula that represents these changes?

A. SA = n (1/8lb) + 1/16B

B. SA = n (1/24lb) + 1/16B

C. SA = n (1/24lb) + 1/4B

D. SA = n (1/12lb) + 1/4B

Question

Kaylee Mccann

Mathematics

26 February, 08:04

If the side length of the base of a square pyramid is divided by 4 and the slant height is divided by 3, what is the surface area formula that represents these changes?

A. SA = n (1/8lb) + 1/16B

B. SA = n (1/24lb) + 1/16B

C. SA = n (1/24lb) + 1/4B

D. SA = n (1/12lb) + 1/4B

+1

Answers (1)

Know the Answer?

Yadira Moses · Answer 1

Base area: B = b²

B 1 = (b/4) ² = b²/16 = B/16

Lateral area:

LA = 4 lb / 2

LA 1 = 4 l / 3 b / 8 = 4 · lb/24, n = 4

SA = LA 1 + B 1

Answer: B) SA = n (1/24 lb) + 1/16 B

If the side length of the base of a square pyramid is divided by 4 and the slant height is divided by 3, what is the surface area formula that represents these changes?A. SA = n (1/8lb) + 1/16BB. SA = n (1/24lb) + 1/16BC. SA = n (1/24lb) + 1/4BD. SA = n (1/12lb) + 1/4B

If the side length of the base of a square pyramid is divided by 4 and the slant height is divided by 3, what is the surface area formula that represents these changes?

A. SA = n (1/8lb) + 1/16B

B. SA = n (1/24lb) + 1/16B

C. SA = n (1/24lb) + 1/4B

D. SA = n (1/12lb) + 1/4B