What is value of x in the equation (x + 4) ^5 = 3125

(x + 4) ^5 = 3125

(x + 4) (x + 4) (x + 4) (x + 4) (x + 4) = 3125

(x² + 4x + 4x + 16) (x² + 4x + 4x + 16) (x + 4) = 3125

(x² + 8x + 16) (x² + 8x + 16) (x + 4) = 3125

(x^4 + 8x³ + 16x² + 8x³ + 64x + 128x + 16x² + 128x + 256) (x + 4) = 3125

(x^4 + 8x³ + 8x³ + 16x² + 16x² + 64x + 128x + 128x + 256) (x + 4) = 3125

(x^4 + 16x³ + 32x² + 320x + 256) (x + 4) = 3125

x^5 + 4x^4 + 16x^4 + 64x³ + 32x³ + 128x² + 320x² + 1280x + 256x + 1024 = 3125

x^5 + 20x^4 + 96x³ + 448x² + 1536x + 1024 = 3125

-1024 - 1024

x^5 + 20x^4 + 96x³ + 448x² + 1536x = 2101

x = 1

(X+4) ^5=3125

Use distributive property for x and 5 and 4 and 5 to get

5x+20=3125

Then subtract 20 from both sides to get

5x=3105

Then divide both sides by 5 to get

X = 621