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18 October, 15:48

What are the coordinates of the vertex of the function f (x) = x^2+10x-3

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  1. 18 October, 15:53
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    (-5,-28)

    Step-by-step explanation:

    f (x) = x^2+10x-3

    Axis of symmetry is - b/2a.

    -10/2 = - 5. This is the x value of the vertex.

    Plug in to solve for y.

    -5^2+10 (-5) - 3 = - 28.
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