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27 June, 16:05

What are the solutions of 2x^2+3x=-8

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  1. 27 June, 16:07
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    The equation given above is written here below with all the terms transposed to only one side of the equation.

    2x² + 3x + 8 = 0

    The quadratic formula used for the determination of the roots is,

    x = (-b + / - sqrt (b² - 4ac)) / 2a

    In the quadratic equation above, we have the numerical coefficients.

    a = 2

    b = 3

    c = 8

    Substituting the known values,

    x = (-3 + / - sqrt (3² - 4 (2) (8)) / (2) (2)

    x = - 0.75 + 1.854i and x = - 0.75 - 1.854i

    By the calculated roots above, it is known that the roots are imaginary.
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