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Zara Parker
Mathematics
27 June, 16:05
What are the solutions of 2x^2+3x=-8
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Milo Montgomery
27 June, 16:07
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The equation given above is written here below with all the terms transposed to only one side of the equation.
2x² + 3x + 8 = 0
The quadratic formula used for the determination of the roots is,
x = (-b + / - sqrt (b² - 4ac)) / 2a
In the quadratic equation above, we have the numerical coefficients.
a = 2
b = 3
c = 8
Substituting the known values,
x = (-3 + / - sqrt (3² - 4 (2) (8)) / (2) (2)
x = - 0.75 + 1.854i and x = - 0.75 - 1.854i
By the calculated roots above, it is known that the roots are imaginary.
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