A company president randomly selects 5 employees to complete a survey. There are 50 employees in the company. In how many different ways can these employees be selected, if the order of selection does not matter?

Question

Jaylan Orozco

Mathematics

10 February, 01:22

A company president randomly selects 5 employees to complete a survey. There are 50 employees in the company. In how many different ways can these employees be selected, if the order of selection does not matter?

+4

Answers (1)

Know the Answer?

Tess Butler · Answer 1

254,251,200

Step-by-step explanation:

This is a combination question, since the order doesn't matter, the formula for combinations is n! / (n-r) ! n is the amount of things we can choose from but r is the amount of things (employees in this case) we actually select. n = 50 and r = 5. This we get 50! / (50-5) ! or 50!/45!, using a calculator, we can find that 50!/45! is equal to 254,251,200. That is our final answer for the amount of combinations available.