4 August, 12:10
Two planes which are 1680 miles apart fly toward each other. Their speeds differ by 40 mph. If they pass each other in 2 hours what is the speed of each?
4 August, 13:12
Speed of slower plane = 400 mph
Speed of the faster plane = 440 mph
Let x be the speed of the slower plane, in mph.
Thus; the speed of the other plane is x + 40 mph.
The distance between two planes decreases at the rate;
x + (x+40) = 2x + 40 mph.
We get the equation
1680 / (2X + 40) = 2.
Solve the equation;
We multiply both sides by (2x + 40), to get
1680 = 2 * (2x + 40),
1680 = 4x + 80,
4x = 1600.
x = 1600/4
= 400 mph.
Therefore; the speed of the slower airplane is 400 mph, while
The speed of the faster is 400 + 40 = 440 mph.
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» Two planes which are 1680 miles apart fly toward each other. Their speeds differ by 40 mph. If they pass each other in 2 hours what is the speed of each?