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4 August, 12:10

Two planes which are 1680 miles apart fly toward each other. Their speeds differ by 40 mph. If they pass each other in 2 hours what is the speed of each?

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  1. 4 August, 13:12
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    Speed of slower plane = 400 mph

    Speed of the faster plane = 440 mph

    Step-by-step explanation:

    Let x be the speed of the slower plane, in mph.

    Thus; the speed of the other plane is x + 40 mph.

    The distance between two planes decreases at the rate;

    x + (x+40) = 2x + 40 mph.

    We get the equation

    1680 / (2X + 40) = 2.

    Solve the equation;

    We multiply both sides by (2x + 40), to get

    1680 = 2 * (2x + 40),

    1680 = 4x + 80,

    4x = 1600.

    Hence,

    x = 1600/4

    = 400 mph.

    Therefore; the speed of the slower airplane is 400 mph, while

    The speed of the faster is 400 + 40 = 440 mph.
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