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18 February, 15:54

Due to smoking, a terminally ill patient loses his lung capacity approximately 2% every 4 months. At this rate, beginning at 100% capacity, what will the patient's lung capacity be in one year?

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  1. 18 February, 16:08
    0
    94.1%

    Step-by-step explanation:

    Convert that 100% to "1." Then:

    Lung capacity as a decimal fraction) = C (x) = 1 (1.00-0.02) ^x, where x represents the number of 4-month periods.

    After the first 4-month period, the lung cap should be 1 (1.00-0.02) ^1, or 0.98.

    After the 2nd 4-month period, 1 (0.98) ^2, and

    After the 3rd 4-month period, 1 (0.98) ^3, or 0.941

    After 1 year (which is after three 4-month periods), the patient's lung cap has declined to 0.941 of its former maximum value (1), or 100%. 0.94 is equivalent to 94.1%.
  2. 18 February, 16:08
    0
    94% lung capacity.

    Step-by-step explanation:

    Find the unit rate. Divide 2 by 4 which gets 0.5.

    Take 0.5 times 12 (12 months in one year)

    You should get 6.

    Then, 100 minus 6 (because the patient loses capacity) therefore you should get 94.
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