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29 September, 13:38

Suppose that the water level of a river is 34 feet and that it is receding at a rate of her foot per day right in equation and how many days it will take to get the water level at 26 feet

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  1. 29 September, 13:56
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    Answer: it will take 9 days

    Step-by-step explanation:

    The water level was initially at 34feet it was receding at the rate of a foot per day. The rate at which it was receding is linear, thus, it is in an arithmetic progression. The formula for the nth term of an arithmetic progression is expressed as

    Tn = a + (n-1) d

    Where

    a is the first term if the sequence

    d is the common difference

    n is the number of terms.

    From the information given,

    a = 34 feet because it is the initial height

    n is the number of days it will take to get to 26 ft

    d = - 1 because it is decreasing by 1 foot per day.

    Tn = T26 = 26 feet. Therefore, the equation will be

    Tn = 34 - 1 (n-1)

    To find for T26,

    26 = 34 + (n - 1) - 1

    26 - 34 = - n + 1

    n - 1 = 8

    n = 8 + 1 = 9
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