6 Given:

2x + y = 0

x - y = 6

What is the solution to the system of equations?

A (1, - 2)

B (2, - 4)

C (4, - 2)

D (5, - 1)

2x + y = 0 (first equation)

x - y = 6 (second equation)

2x + y = 0 (first equation)

2x - 2y = 12 (second equation multiplied by 2 so that the x is the same)

3y = - 12 (second equation subtracted from first to find y)

y = - 4 (-12 divided by 3 to find y)

2x - 4 = 0 (y substituted into equation)

2x = 4 (-4 moved to other side so we can isolate 2x)

x = 2 (4 divided by 2 to find x)

The answer is (2, - 4), as we worked out that x is 2, and y is - 4.