What is the value of the range of the function f (x) = x squared + 2 for the domain value 1/4?

a.) y=2

b.) y=2 1/4

c.) y = 2 1/8

d.) y = 2 1/16

Question

Rylee Fisher

Mathematics

18 April, 18:25

What is the value of the range of the function f (x) = x squared + 2 for the domain value 1/4?

a.) y=2

b.) y=2 1/4

c.) y = 2 1/8

d.) y = 2 1/16

+4

Answers (2)

Know the Answer?

Daniels · Answer 1

Ur looking for the range ... so u r looking for f (x) or y ... and x = 1/4

f (x) = 1/4^2 + 2

f (1/4) = 1/4 * 1/4 + 2

f (1/4) = 1/8 + 2

f (1/4) = 1/8 + 16/8

f (1/4) = 17/8 which equals 2 1/8 ... so y = 2 1/8

Jordon Webb · Answer 2

I think the answer is d

What is the value of the range of the function f (x) = x squared + 2 for the domain value 1/4?a.) y=2b.) y=2 1/4c.) y = 2 1/8d.) y = 2 1/16

What is the value of the range of the function f (x) = x squared + 2 for the domain value 1/4?

a.) y=2

b.) y=2 1/4

c.) y = 2 1/8

d.) y = 2 1/16