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18 April, 18:25

What is the value of the range of the function f (x) = x squared + 2 for the domain value 1/4?

a.) y=2

b.) y=2 1/4

c.) y = 2 1/8

d.) y = 2 1/16

+4
Answers (2)
  1. 18 April, 18:40
    0
    Ur looking for the range ... so u r looking for f (x) or y ... and x = 1/4

    f (x) = 1/4^2 + 2

    f (1/4) = 1/4 * 1/4 + 2

    f (1/4) = 1/8 + 2

    f (1/4) = 1/8 + 16/8

    f (1/4) = 17/8 which equals 2 1/8 ... so y = 2 1/8
  2. 18 April, 18:52
    0
    I think the answer is d
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