3c-2 (c+10) = 7c-5 (c+2)

Answer: C = - 10

Step-by-step explanation: First step: simplify both sides of the equation

3c-2 (c+10) = 7c-5 (c+2)

3c + (-2) (c) + (-2) (10) = 7c + (-5) (c) + (-5) (2) (Distribute)

3c+-2c+-20=7c+-5c+-10

(3c+-2c) + (-20) = (7c+-5c) + (-10) (Combine Like Terms)

c + - 20 = 2c - 10

c - 20 = 2c - 10

Step 2: Subtract 2c from both sides

c - 20 - 2c = 2c - 10 - 2c

-c-20=-10

Step 3: Add 20 to both sides

-c-20+20=-10+20

-c=10

Step 4: Divide both sides by - 1

-c/-1 = 10/-1

C=-10