What is the solution to the equation 2 (4 minus 3 x) + 5 (2 x minus 3) = 20 minus 5 x?

a. x = - 13

b. x = StartFraction 5 Over 4 EndFraction

c. x = StartFraction 13 Over 2 EndFraction

d. x = 3

D. x=3

Do distributive property on the 2 (4-3x) and the 5 (2x-3) to then get

8-6x+10x-15=20-5x

Then do leave change opposite to get

8+-6x+10x+-15=20+-5x

Then add the - 6x+10x = 4x and add 8+-15=-7

-7+4x=20+-5x

Then add 7+20=27 and add 4x+5x=9x

9x=27

Divide 9 from 27

And then you get x=3

D = x=3