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10 July, 04:10

Solve for the perimeter and area of a rectangle that has a length of 4in. and a width of 2 in

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Answers (2)
  1. 10 July, 04:12
    0
    P=4+4+2+2

    =8+4

    =12in

    A=l*w

    =4*2

    =8in^2
  2. 10 July, 04:12
    0
    The perimeter is either 10 (if the rectangle has two sides that are 4in and one side that is 2in) or 8 (if the rectangle has two sides that are 2in and one side that is 4in)
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