Solve for the perimeter and area of a rectangle that has a length of 4in. and a width of 2 in

P=4+4+2+2

=8+4

=12in

A=l*w

=4*2

=8in^2

The perimeter is either 10 (if the rectangle has two sides that are 4in and one side that is 2in) or 8 (if the rectangle has two sides that are 2in and one side that is 4in)