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Hailey Rodgers
Mathematics
4 April, 13:14
Ab + cd-bd-ac = a (b-c) + d (c-b)
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Ella Hooper
4 April, 13:38
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ab + cd-bd-ac = a (b-c) + d (c-b)
Step-by-step explanation:
ab+cd-bd-ac
Let us first bring the like terms together
Like terms are those terms which have same variables and same exponents also. Hence in this case we do not any like terms.
Hence we will take those two terms together which has atleast one same variable
ab and ac
cd and bd
ab-ac+cd-bd
now taking a as GCF in first two terms and d as GCF in last two terms
a (b-c) + d (c-b)
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