Ask Question
21 February, 10:02

If x+y+z=0 Prove that (x^2+y^2+z^2) = 4 (xy+xz+yz) ^2

+3
Answers (1)
  1. 21 February, 10:25
    0
    X + y + z = 0

    (x + y + z) ² = 0

    x² + y² + z² + 2xy + 2xz + 2yz = 0

    x² + y² + z² = - 2 (xy + xz + yz)

    (x² + y² + z²) ² = 4 (xy + xz + yz) ²

    eh, not same
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If x+y+z=0 Prove that (x^2+y^2+z^2) = 4 (xy+xz+yz) ^2 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers