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Find all solutions in the interval [0, 2π).

sin^2 x + sin x = 0

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  1. 27 May, 20:19
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    Factoring:-

    sin x (sin x + 1) = 0

    sin x = 0, or sinx + 1 = 0 giving sin x = - 1

    when sin x = 0 x = 0, pi

    when sin x = - 1, x = pi + pi/2 = 3pi/2

    solutions in given interval are 0, pi and 3pi/2
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