Solve the system equations

y=x^2-8 4x+y=-8

Insert y in the second equation and solve for x:

4x + (x^2-8) = - 8

4x+x^2-8=-8

4x+x^2=0

x^2+4x=0

x = - 4

Now you insers this x-value in the first or second equation (i use the first):

y = (-4) ^2-8=16-8=8

Therefore the conclusion must be x=-4 and y=8