If a coin is tossed 3 times, and then a standard six-sided die is rolled 4 times, and finally a group of four cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?

Question

Sarai Reynolds

Mathematics

17 March, 12:32

If a coin is tossed 3 times, and then a standard six-sided die is rolled 4 times, and finally a group of four cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?

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Answers (1)

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Kamden Bond · Answer 1

67,365,043,200

Step-by-step explanation:

A coin toss has 2 possible outcomes. A coin tossed 3 times has 2³ = 8 possible permutations.

A standard die has 6 possible outcomes. A die rolled 4 times has 6⁴ = 1296 possible permutations.

The number of ways 4 cards can be chosen from a deck of 52 without replacements is 52*51*50*49 = 6,497,400.

The total number of possible outcomes is:

8 * 1296 * 6,497,400 = 67,365,043,200