Ask Question

Let f (x) = cos (arctanx). What is the range of f?

(a) {x| - (pi/2) (a) {x|0 (a) {x|0 = (a) {x|-1 (a) {x|-1=

+3
Answers (1)
  1. 24 May, 14:48
    0
    -π/2 < arctan (x) < π/2

    So cos (π/2) < cos (arctan (x)) < cos (0)

    0 < cos (arctan (x)) < 1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Let f (x) = cos (arctanx). What is the range of f? (a) {x| - (pi/2) (a) {x|0 (a) {x|0 = (a) {x|-1 (a) {x|-1= ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers