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Carlo
Mathematics
5 October, 12:58
Find the zeroes of polynomial x² - (√3+1) x+√3
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London Barr
5 October, 13:11
0
X² - √3x - x + √3
x (x-√3) - (x-√3)
(x-√3) (x-1)
zeroes are x-√3 = 0
x = √3
and x-1 = 0
x = 1
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