A car's stopping distance in feet is modeled by the equation d (v) = 2.15v^2/58.4f where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate stopping distance of the car?
a. 21 feet
b. 21 miles
c. 239 feet
d. 239 miles
Answers (1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A car's stopping distance in feet is modeled by the equation d (v) = 2.15v^2/58.4f where v is the initial velocity of the car in miles per ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers
You Might be Interested in
Write a word phrase for the expression 3 (w-1) then simplify
Answers (1)
A rectangular tank of 12 m long, 11 m wide and 13 m deep held water to a depth of 7 m. What is the volume of water to be added to fill up the tank?
Answers (1)
Write the sum as a product of the gcf of the two numbers 75+90
Answers (1)
What is greater 5.624 or 5.64
Answers (1)
What is a mixed number for 7/12
Answers (1)
New Questions in Mathematics
5 times 23 times 2 equals what
Answers (1)
How can i share an circle pizza with 12 people!.
Answers (2)
How many days in a week?
Answers (1)
you deposit $1.000 in a saving account that earns 0.5% each month. Assuming you do not deposit or withdraw any from the account, how much will you have in the account after 3 years?
Answers (1)
Determine whether (18+35) x4=18 + 35x4 is true or false. explain
Answers (1)