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30 January, 18:54

A car's stopping distance in feet is modeled by the equation d (v) = 2.15v^2/58.4f where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate stopping distance of the car?

a. 21 feet

b. 21 miles

c. 239 feet

d. 239 miles

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Answers (1)
  1. 30 January, 19:17
    0
    c. 239 feet is correct
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