A car's stopping distance in feet is modeled by the equation d (v) = 2.15v^2/58.4f where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate stopping distance of the car?
Home » ⭐️ Mathematics » A car's stopping distance in feet is modeled by the equation d (v) = 2.15v^2/58.4f where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.