Given P (A) 0.169, P (B) 0.041, and P (C) 0.172, and that events A, B, and C are mutually exclusive, what is the P (A or B or C) ? Answer in decimal form. Round to 3 decimal places as needed Your Answer: Answer

The value of P (A or B or C) is 0.382.

Step-by-step explanation:

Given,

P (A) = 0.169,

P (B) = 0.041,

P (C) = 0.172

Since, if events A, B and C are mutually events (in which no element is common),

Then, P (A∪B∪C) = P (A) + P (B) + P (C)

Or P (A or B or C) = P (A) + P (B) + P (C),

By substituting the values,

P (A or B or C) = 0.169 + 0.041 + 0.172 = 0.382