Two weather tracking stations are on the equator 165 miles apart. A weather balloon is located on a bearing of N 40°E from the western station and on a bearing of N 22°E from the eastern station. How far is the balloon from the western station?

Ok here we go

Regular triangle with : bearing from the western station = 90° - 40° = 50° bearing from the eastern station. = 90° + 22° = 112° - > the third angle : 18° There for the distance from balloon to the west station: x / sin112 = 165 / sin 18.

I think i nailed this ...