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Sanai Aguilar
Mathematics
9 November, 13:39
X+3y=15 and 4x+2y=30
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Powder
9 November, 13:50
0
Subsitution
minus 3y from both sides in the first equatio
x=15-3y
subsitute 15-3y for x in other equation
4 (15-3y) + 2y=30
60-12y+2y=30
60-10y=30
minus 60 both sides
-10y=-30
divide both sides by - 10
y=3
sub back
x=15-3y
x=15-3 (3)
x=15-9
x=6
(x, y)
(6,3)
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