Admission to the circus is $16 for adults and eight dollars for children write an expression to find the total cost of three adult tickets and 8 children's tickets then find the total cost

The total cost is $112.

The cost was found using this expression: 16 (3) + 8 (8)

Step-by-step explanation:

To find the cost of any ticket, you would multiply the ticket cost by the number of tickets.

For adult tickets, you would multiply 16 by the number of tickets. This can be represented algebraically.

let 'a' be the number of adult tickets

16a

For children's tickets, you would multiply 8 by the number of tickets. Algebraically, it is:

let 'c' be the number of children's tickets

8c

If you wanted to buy both ticket types, you would add each product. The total cost of tickets is:

16a + 8c This is the general expression

If we want to buy 3 adult tickets and 8 children's tickets, substitute a = 3 and c = 8 into 16a + 8c.

16a + 8c

= 16 (3) + 8 (8) Multiply each pairs of factors

= 48 + 64 Add

= 112 Total cost

Write in the dollar sign $.

Therefore the total cost of three adult tickets and eight children's tickets is $112.