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27 February, 09:17

Calculate the surface area of the portion of the surface z=x^2 + y that lies above the triangular region t wth vertices 0,0 4,0 and 4,2

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  1. 27 February, 09:31
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    Z=x^2+y

    Z = (0) ^2+0=0

    Z = (4) ^2+0=16

    Z = (4) ^2+2=18

    Z total = 34
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