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Emma Atkinson
Mathematics
8 October, 15:28
What are the solutions of 2x2 3x = - 5?
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Kirby
8 October, 15:34
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I'm guessing the equation is 2x^2-3x=-5
If this is the case, then you need to set the equation to equal 0 by moving the - 5 to the left side of it
2x^2-3x+5=0
The you can factor the equation
(2x-5) (x+1) = 0
now solve for each factor
2x-5=0 is x=5/2x
x+1=0 is x=-1
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