What are the solutions of 2x2 3x = - 5?

I'm guessing the equation is 2x^2-3x=-5

If this is the case, then you need to set the equation to equal 0 by moving the - 5 to the left side of it

2x^2-3x+5=0

The you can factor the equation

(2x-5) (x+1) = 0

now solve for each factor

2x-5=0 is x=5/2x

x+1=0 is x=-1