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26 November, 16:26

Solve the equation: 4a^2-12a - (a-3) = 0

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Answers (2)
  1. 26 November, 16:55
    0
    Two solutions were found:

    a = 1/4 = 0.250

    a = 3
  2. 26 November, 16:56
    0
    ((13 + √217) / 8; (13 - √217) / 8)

    Step-by-step explanation:

    4a^2-12a - (a-3) = 0

    4a^2 - 12a - a - 3 = 0

    4a^2 - 13a - 3 = 0

    a1 = (13 + √217) / 8

    a2 = (13 - √217) / 8
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