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17 June, 23:40

If you stand on a ship in a calm sea, then your height x (in feet) above sea level is related to the farthest distance y (in miles) that you can see by the equation: y=sqrt (1.5x + (x/5280) ^2) how high up do you have to be to be able to see 10mi?

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  1. 18 June, 00:04
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    We are given the relation between the height (in feet) and the distance (in miles) as follows:

    y = sqrt (1.5x + (x/5280) ^2).

    We want to know the height (x) that makes the distance (y) = 10 miles

    So, we will simply substitute in the above equation with y = 10 and calculate x as follows:

    10 = sqrt (1.5x + (x/5280) ^2)

    we will square both sides to get rid of the root:

    100 = 1.5x + (x/5280) ^2

    1.5x + (x/5280) ^2 - 100 = 0

    (x-66.11475) (x+7986.1147) = zero

    either x = 66.11475 feet (accepted solution)

    or x = - 7986.1147 feet (rejected solution as no height is in negative)
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