A sparkling-water distributor wants to make up 200 gal of sparkling water to sell for $ 5.00 per gallon. She wishes to mix three grades of water selling for $10 .00, $1 .00, and $4.50 per gallon, respectively. She must use twice as much of the $4.50 water as the $ 1.00 comma water. How many gallons of each should she use?

Question

Orr

Mathematics

22 November, 04:30

A sparkling-water distributor wants to make up 200 gal of sparkling water to sell for $ 5.00 per gallon. She wishes to mix three grades of water selling for $10 .00, $1 .00, and $4.50 per gallon, respectively. She must use twice as much of the $4.50 water as the $ 1.00 comma water. How many gallons of each should she use?

+2

Answers (2)

Know the Answer?

Berger · Answer 1

The answer will be D

Alisha Marks · Answer 2

x=50

y=50

z=100

Step-by-step explanation:

Let x = $10

y = $1

z = $4.5

2y=z

5 * 200 = 1000 Dollars wanted

1000 = 10x + y + 4.5z

variables represent number of gallons of each type

1000 = 10x + y + 4.5 (2y) sub z for y

x=50

y=50

z=100